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[f-cpu] Scheduler
I send you a scheme of a bypass net.
The "Active" signal is the number of the active unit. On the same
pipeline stage, there is only one active unit. For each active stage, i
compare the address of the 2 write registers to the 2 registers in use
by the instructions of the stage. I only drawn the system for one
register (not the 3 read register) and only for one pipeline stage.
I try to make a more clear one.
nicO