Well, this is a good idea, I go do this way. tks
2012/8/22 Greg Ewing
<greg.ewing@xxxxxxxxxxxxxxxx>
Ricardo Franco wrote:
  That's why when you are comparing floating point numbers, you always
  have to check if they are within some small error value from each
  other. How large that value is depends on your particular use case.
equality at all. You can do that in this case by using an
integer loop counter and computing the float value from it:
>>> for i in xrange(11):
... Â Ârate = 1.0 + i * 0.1
... Â Âprint rate
...
1.0
1.1
1.2
1.3
1.4
1.5
1.6
1.7
1.8
1.9
2.0
--
Greg