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Re: [pygame] How the get a font size
You can also just violate the object by giving it an extra attribute:
f = pygame.font.Font(filename, size)
f.new_attribute = size
I'm pretty sure any OO enthusiast would applaud this method. There is
certainly nothing bad that can be said about my method. No sir. =D
-Thiago
On Tue, Jan 13, 2009 at 12:48 AM, James Paige <Bob@xxxxxxxxxxxxxxxxxxx> wrote:
> Seems to me like this should work:
>
> class SizeFont(pygame.font.Font):
>
> def __init__(self, filename, size):
> pygame.font.Font.__init__(self, filename, size)
> self.size = size
>
> ---
> James Paige
>
> On Mon, Jan 12, 2009 at 04:07:11PM -0600, Jake b wrote:
>> Create a basic Font() wrapper. When you create the font, save the size.
>> On Mon, Jan 12, 2009 at 2:02 AM, Luca <lucafbb@xxxxxxxxx> wrote:
>>
>> On Sun, Jan 11, 2009 at 10:36 PM, Noah Kantrowitz <noah@xxxxxxxxxxxxxx>
>> wrote:
>>
>> >> As far as I know, there's no way to get the size of the font that
>> way.
>> >> What I do is name the font names in an intuitive way:
>> >> Font12 = pygame.font.Font("....", 12)
>> >> Font18 = pygame.font.Font("....", 18)
>> >> Font36 = pygame.font.Font("....", 36)
>>
>> Thanks all, but in this way is impossible to get the size on an unknow
>> font? I'm making a library for developer that need to know what is the
>> font size that the developer can have choosen...
>>
>> --
>> -- luca
>>
>> --
>> Jake
>