Because rectangles can overlap, it's possible to reduce the amount drawing done when using them for dirty rect updating. If there's two rectangles overlapping, then we don't need to over draw the overlapping area twice. Normally the dirty rect update algorithm used just makes a bigger rectangle which contains two of the smaller rectangles. But that's not optimal.But, as with all over draw algorithms, can it be done fast enough to be worth it?Here's an article on the topic:
http://gandraxa.com/detect_overlapping_subrectangles.xml
jmm0 made some code here:
https://bitbucket.org/jmm0/optimize_dirty_rects/src/ c2affd5450b57fc142c919de10e530 e367306222/optimize_dirty_ rects.py?at=default& fileviewer=file-view-default
DR0ID, also did some with tests and faster code...
https://bitbucket.org/dr0id/pyweek-games/src/ 1a9943ebadc6e2102db0457d17ca3e 6025f6ca60/pyweek19-2014-10/ practice/dirtyrects/?at= default
So far DR0ID says it's not really fast enough to be worth it. However, there are opportunities to improve it. Perhaps a more optimal algorithm, or one which uses C or Cython.
"worst case szenario with 2000 rects it takes ~0.31299996376 seconds"
If it's 20x faster in C, then that gets down to 0.016666. Still too slow perhaps.It's not an embarrassingly parallel problem... I think. But I haven't thought on it much at all. Maybe there is a use for multi core here.Anyone done any other work like this? Or know of some good algos for this?cheers,