Re: [pygame] Error On Pygame Simple Game

[Samuel Mankins <waterflight@xxxxxxxxxxxxx>]

Your indentation was wrong--Python is whitespace sensitive, so you've 
got to be careful. I recommend getting something like Emacs, which is 
free, and "understands" Python, so that pressing tab will cycle through 
the possible indentations. Here's the fixed version:
import sys, pygame
pygame.init()

size = width, height = 320, 240
speed = [2, 2]
black = 0, 0, 0

screen = pygame.display.set_mode(size)

ball = pygame.image.load("ball.bmp")
ballrect = ball.get_rect()

while 1:
       for event in pygame.event.get():
           if event.type == pygame.QUIT: sys.exit()

   ballrect = ballrect.move(speed)
   if ball.rect.left < 0 or ball.rect.right > width:
       speed[0] = -speed[0]
   if ball.rect.top < 0 or ball.rect.bottom > height:
       speed[1] = -speed[1]

   screen.fill(black)
   screen.blit(ball, ball.rect)
   pygame.display.flip()

Also, I don't think using the ballrect variable works, you just have to 
do ball.rect directly, unless at the end of every update you say 
'ball.rect = ballrect'.
Good luck with pygame!


RR4CLB wrote:
> Hi!
>
>     I am just getting started in Pygame and the simple program below dies on line 4. I suspect that the command 3D is the problem. So, is this format/syntax all wrong for learning pygame? Or is something not declared?
>
> Simple Program:
> import sys, pygame
> pygame.init()
>
> size = width, height = 320, 240
> speed = [2, 2]
> black = 0, 0, 0
>
> screen = pygame.display.set_mode(size)
>
> ball = pygame.image.load("ball.bmp")
> ballrect = ball.get_rect()
>
> while 1:
>         for event in pygame.event.get():
>             if event.type == pygame.QUIT: sys.exit()
>
>     ballrect = ballrect.move(speed)
>     if ballrect.left < 0 or ballrect.right > width:
>     speed[0] = -speed[0]
>     if ballrect.top < 0 or ballrect.bottom > height:
>        speed[1] = -speed[1]
>
>     screen.fill(black)
>     screen.blit(ball, ballrect)
>     pygame.display.flip()
>
>
>
>
>