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Re: [tor-dev] [Discussion] 5 hops rendezvous circuit design
On Tue, Feb 11, 2014 at 11:55:05AM -0500, Qingping Hou wrote:
> (0) client fetches descriptor for a hidden service.
> (1) client connects to introduction point.
> (2) since client and HS are connected via introduction point, they can
> negotiate a random number using this channel.
> (For more details, see [RAND_NEGO])
> (3) both client and HS maps that random number to a random onion router
> using the same scheme, so they end up with the same node.
> This is the candidate RP.
> (4) both client and HS create a 3 hops circuit using RP as last hop.
> (5) RP joins the circuit originates from HS to the circuit originates
> from client.
> (6) now client and HS are connected. Because their original circuits
> share the same endpoint(the RP), the length of the path is 5 hops.
Worth discussing.
> to the whole process. Firstly, it reuses the connection to introduction
> point for both sides so it requires no extra circuits build up.
> Secondly, the bottle neck is circuit setup, cell/stream transmission
> delay is actually pretty low.
To be clear, the client is the one who learns first what the RP should
be, yes? That means:
A) The problem George brought up -- the client can keep doing this dance
until they agree upon an RP that the client controls, and now the HS
effectively has a two-hop path to the RP. Maybe that is ok (two is still
more than one), but it should be made clear.
B) The client should extend a circuit to RP first, establish a rendezvous
cookie there, and only then respond to HS with its R_a and rend cookie?
Otherwise there will be a race where both sides try to extend to RP, and
it's unspecified what happens if HS gets there first.
> Note that at step 2), if HS is able to recover R_a from H(R_a), it can take
> control over R_c. So to mitigate this, we can use a variant of
> Diffie-Hellman handshake:
>
> (1) client generates a public key g^x and sends the digest H(g^x) to HS
> (2) HS remembers H(g^x), generates a public key g^y and sends it back
> to the client
> (3) client receives g^y and sends back g^x to HS
> (4) HS checks g^x against H(g^x) to make sure it's not generated after
> client receives g^y.
> (5) Now both client and HS compute a shared random number: R_c = g^(xy)
You're making both sides do public key operations just because the hash
function might be broken? I would guess the load, and DoS opportunities,
introduced by public key operations on the HS side will outweigh any
theoretical benefits here.
> This is where hop negotiation come into play. A negotiated hop is
> guaranteed to be a random node and cannot be determined by anyone.
For a single run this is true, but for the repeated game it's not. This
might be the killer flaw here.
> a) How to design the scheme for mapping a random number to the same node
> between client and server?
This one will indeed be tricky, since each side can have one of several
"currently valid" views of the network (i.e. consensus networkstatus
documents).
--Roger
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