Re: [pygame] Testing for button in a table in OcempGUI

[Johan Geldenhuys <johan@xxxxxxxxxxxxxxx>]

Thanks, Laura,

That helps a lot and it works! My next challange is to look at letters in my grid that must be there not to be overwritten by another letter from a other ligitimate word.

Johan

Laura Creighton wrote:

In a message of Thu, 29 Dec 2005 19:26:00 +0200, Johan Geldenhuys writes:
  

Marcus,
I tried this
"""
try:
    for i in range(tbl_words.rows):
      
       for j in range(tbl_words.columns):
           letter = self.letters()
           button = Button(letter)
           button.border = BORDER_NONE
    

 >            button.padding = 0
  

          
           button.connect_signal(SIG_CLICKED, self.clicked, button, i, 
j, letter)
          
           tbl_words.add_child(i, j, button)
           self.button_list(i, j, letter)
except:
       pass
"""
I am not sure what to put in at the except part. With the above, it 
stops as soon as it gets to the first position that is already occupied. 
Any ideas what to use there?

I will look at the docs.
Johan
    

It should look more like this pseudo-code:

     already_have_a_letter_waiting = False
     for i in range(tbl_words.rows):
        for j in range(tbl_words.columns):
            if not already_have_a_letter_waiting:
	        letter = self.letters()
                button = Button(letter)
                button.border = BORDER_NONE
                button.padding = 0
                already_have_a_letter_waiting = True:
	    try:
		# here comes the stuff that causes the exception
                tbl_words.add_child(i, j, button)
                button.connect_signal(SIG_CLICKED, self.clicked, button, 
                                      i,j, letter)
                self.button_list(i, j, letter)
		already_have_a_letter_waiting = False
	   except PasteInWhateverExceptionYouGetFromYourTraceback:
		already_have_a_letter_waiting = True

Laura